There are 576 boys and 448 girls in a school that are to be divided into equal sections of either boys or girls alone. The total number of sections thus formed are:

The total numbers of sections are 16.

Step-by-step explanation:

Given:

Number of boys in school = 576

Number of girls in school = 448

To find: Total Number of sections such that each section has either boys or girls.

Height Common Factor ( HCF ) of both number gives the number of students in a section.

HCF of 576 and 448

576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3

448 = 2 × 2 × 2 × 2 × 2 × 2 × 7

HCF = 2 × 2 × 2 × 2 × 2 × 2 = 64

Number of sections of Boys = 576/64 = 9

Number of sections of girls 448/64 = 7

Total Number of sections = 9 + 7 = 16

Therefore, The total numbers of sections are 16.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

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