Find the 40th term of an AP where 12th term is 45 and 17th term is 80.

40th term = 241.

Step-by-step explanation:

17th term:

=  a1 + 16d = 80

12th term

=  a1 + 11d = 45       Subtracting the 2 equations:

5d = 80 - 45 = 35

d = 7

and a1 + 16(7) = 80

a1 = 80 -112 = -32.

Therefore the 40th term = -32 + 39*7

= 241.

bru

step-by-step explanation:

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .