PLEASE HELP QUESTION ATTACHED

(6,3)

Step-by-step explanation:

x + 3y = 15

4x + 2y = 30

This system of equations can either be solved by elimination method or substitution method or both

We are going to use both method to solve this system of education

First we are gong to use elimination method to find the value of y

x + 3y = 15 (1)

4x + 2y = 30 (2)

Using the elimination method, to eliminate x, we want to make coefficients of x the same, to do that we multiply equation (1) by 4

4x + 12y =60 (3)

subtract equation (2) from equation (3)

(4x-4x =0        12y - 2y = 10y        60 -30=30 )

We will have;

10y = 30    

Divide 10 by both-side of the equation

10y/10  =  30/10

y = 3

We will use substitution method to get the value of x,

We will now substitute y=3 in  equation (1)

    x + 3y = 15

      x  + 3(3) = 15

    x + 9  = 15

Subtract 9 from both-side of the equation

x +9 - 9 = 15 -9

x    =  6

The solution to the system of the equations is x=6 and y =3

(6, 3)

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it