3. If mZEFH = (5x + 1), mZHFG = 62°, and
mZEFG = (18x + 11), find each measure.

Answer/Step-by-step explanation:

Given:

m<EFH = (5x + 1)°

m<HFG = 62°

m<EFG = (18x + 11)°

Required:

1. Value of x

2. m<EFH

3. m<EFG

SOLUTION:

1. Value of x

m<EFH + m<HFG = m<EFG (angle addition postulate)

(5x + 1) + 62 = (18x + 11)

Solve for x using this equation

5x + 1 + 62 = 18x + 11

5x + 63 = 18x + 11

Subtract 18x from both sides

5x + 63 - 18x = 18x + 11 - 18x

-13x + 63 = 11

Subtract 63 from both sides

-13x + 63 - 63 = 11 - 63

-13x = -52

Divide both sides by -13

-13x/-13 = -52/-13

x = 4

2. m<EFH = 5x + 1

Plug in the value of x

m<EFH = 5(4) + 1 = 20 + 1 = 21°

3. m<EFG = 18x + 11

m<EFG = 18(4) + 11 = 72 + 11 = 83°

if you are looking for the unit rate then the answer would be 9 because unit rate is distance divided by time.

step-by-step explanation:

we can't see all full 4 options, but if this is the full option, than the very left one is correct:

-2/5 * -3 3/4

remake the question, adding a picture of all the question, or write down the full left and right answers.