PLEASE HELP Q is in the interior of angle XYZ.
The measure of angle XYZ = 3r +2.
The measure of angle XYQ = 2r-1.
The measure of angle ZYQ = 3r-5.
True
False
r = -3
The measure of angle XYQ = 7
10
r = 4
Ray YQ bisects angle XYZ.

r=-3 FALSE

m<XYQ=7 TRUE

r=4 TRUE

Ray YQ bisects angle XYZ TRUE

Step-by-step explanation:

2r-1+3r-5=3r+2

5r-6=3r+2

2r=8

r=4

r=-3 FALSE

m<XYQ=7 TRUE (XYQ=2r-1=2(4)-1=8-1=7)

r=4 TRUE

Ray YQ bisects angle XYZ TRUE  (ZYQ=3r-5=3(4)-5=12-5=7.  Both XYQ and ZYQ=7, so ray YQ is the bisector)

I don't know what the 10 is for in your question.

muyb ajo

step-by-step explanation:

jegosu

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: