5. Find the point X on CF that is of the distance from C to F. C is -4 F is 5 -7-6-5-4-3-2-1 0 1 2 3 4 5 6 7 A) -2.2 B) 0.5 C) -1.8 D) -3

Correct Question: Find the point X on CF that is ⅕ of the distance from C to F.

*See attachment below for the numberline.

A.) -2.2

Step-by-step explanation:

Given that C on the numberline = -4,

F on the numberline = 5

The distance from point C (-4) to point F (5) = |-4 - 5| = |-9| = 9

We are told that point X on CF, = ⅕ of the distance from point C to F. That is, X on the numberline is ⅕ of 9 = ⅕*9

⅕*9 = 9/5 = 1.8

This means, the coordinate of point X, from point C = coordinate of C + 1.8 = -4 + 1.8 = -2.2.

Therefore, the coordinate of X that is ⅕ of the distance from point C to F is -2.2.

the line of

6 equilateral triangles