11. An AC waveform has a peak voltage of 50 VAC. What's the waveform's RMS voltage?
O A. 50.0 VAC
B. 35.4 VAC
C. 24.8 VAC
O D.52.8 VAC

Option B - 35.4 VAC

Step-by-step explanation:

Formula for peak voltage is;

V_p = V_rms × √2

Making V_rms the formula, we have;

V_rms = (V_p)/√2

We are given:Peak voltage: V_p = 50 VAC

Where 50 VAC means 50 Volts AC power

Thus;

V_rms = 50/√2

V_rms ≈ 35.4 VAC

So option B is correct

x/7.50 = 15

x= 7.50 / 15 divide

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1