I don't have a graph. Does anyone know how to do this without a graph?

10

Step-by-step explanation:

you would go to desmos graphing calculator and plug in the 2 points and you can see that it goes 8 down and 6 right and when you do Pythagorean theorem you get 64+36 which is 100 and the square root of that is 10 so the distance would be 10 units or simply 10

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

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