A technical machinist is asked to build a cubical steel tank that will hold 60L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.01m.

Step-by-step explanation:

This problem bothers on the mensuration of solids, cube

Step one:

The volume of the tanks will hold 60L of water

hence the volume of the tank is 60L

we know that the expression for the

volume of cube = L*L*L

Volume of cube = L^3

60= L^3

L=  √60

L= 7.7459

To the nearest 0.01m we have  L= 7.75 m

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: