You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i. e., parentheses) accurate to twp decimal places.

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean =

mean = 15.58

the standard deviation =

the standard deviation =

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E =

The Margin of Error M.O.E =

The Margin of Error M.O.E =

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( )

The  Confidence interval = ( , )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

answer: you need the equation in the question so i can answer it

step-by-step explanation: