If m∠ TUW = (5x + 3)°, m∠WUV=(10x-5)°, and m∠TUV=(17X-16)°, find each measure

m∠ TUW =  38°

m∠WUV =  12°

m∠TUV =  103°

Step-by-step explanation:

Given: m∠ TUW = (5x + 3)°, m∠WUV=(10x-5)°, and m∠TUV=(17x-16)°

Since, m∠TUV = m∠ TUW  +  m∠WUV

So, 17X-16 = (5x + 3) + (10x-5)

⇒ 17X-16 = 5x + 3 + 10x-5   [open parenthesis]

⇒  17X-16 =5x +  10x +3 -5   [combine like trems]

⇒  17X-16 =15x -2

⇒   17X -15x = -2+16     [subtract 15x and add 16 on both sides]

⇒   2x = 14        

⇒  x= 7               [divide both sides by 2]

Now, m∠ TUW = (5(7) + 3)°=  38°

m∠WUV=(10(7)-5)° =  12°

m∠TUV=(17(7)-16)° =  103°

Hence,  m∠ TUW =  38°

m∠WUV =  12°

m∠TUV =  103°

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

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