The side lenghts of a square measures 10x+5. the side lenghts of a triangle are 30x,3x and 6x+30. the square and triangle have the same perimeter. find the perimeter PLEAS HELPP<333

58

Step-by-step explanation:

We can use the Pythagorean theorem to find the area of the square for the third side.

The equation for the Pythagorean theorem is

a^2 + b^2 = c^2

where a and b are the lengths of the two legs of the triangle, and c is the length of the hypotenuse.

a^2 + b^2 = c^2

3^2+7^2=x^2

9+49=x^2

58=x^2
The area of the square for the third side of the triangle is 58 units^2 squared.

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step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.