Choose the algebraic expression that represents the area of a triangle that has a base 8 inches less than 2 times wider than the hight.? A. (1/2)(2b+8)(b)
B. (1/2)(2h-8)(h)
C. (1/2)(2h)(h-8)

I’m not sure if it’s either B or C

B. (1/2)(2h-8)(h)

Step-by-step explanation:

Area of a triangle = 1/2 × base × height

Let

Height = h

Base = 8 inches less than 2 times wider than the hight

= 2h-8

Substituting the values of base and height into the formula

We have,

Area of a triangle = 1/2 × base × height

= 1/2 × (2h-8) × h

= (1/2)(2h-8)(h)

The correct answer is option

B. (1/2)(2h-8)(h)

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet