A person had $18,000 invested in two accounts, one paying 8% simple interest and one paying 9% simple interest. How much was invested in each account if the interest after 1 yr is $1606?

he Invested $11,000 in the 5% interest account and $ 7,000 in the 10% interest account.

Step-by-step explanation:Step-by-step explanation:

Let x and y represent the amount he Invested in the two accounts (5% and 10% respectively)

Given that the total investment is $18,000

x + y = 18000 1

If he earned a total of $1,250 in interest in 1 year.

0.05(x) + 0.10(y) = 1250 2

Solving the simultaneous equation,  

Divide equation 2 through by 0.05

x + 2y = 25000 3

Subtract equation 1 from 3

x-x + 2y-y = 25000-18000

y = 7000

From equation 1

x = 18000 - y = 18000 - 7000

x = 11000

Therefore, he Invested $11,000 in the 5% interest account and $ 7,000 in the 10% interest account.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

step-by-step explanation:

their are no angles. sorry cant .