Simplify to create an equivalent expression. 8k−5(−5k+3) Choose 1 A 33k+15 B 33k-15 C 3k+3 D 3k-3

(a) (8%) compute the probability of an even integer among the 100 integers 1! , 2! , 3! , until 100! (here n! is n factorial or n*(n-1)*(n-2) *… 1) (b) (16%) compute the probability of an even integer among the 100 integers: 1, 1+2, 1+2+3, 1+2+3+4, …., 1+2+3+… + 99, and 1+2+3+… + 100

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Why is partitioning a directed line segment into a ratio of 1: 3 not the same as finding the length of the directed line segment?