Given directed line segment ab find the coordinates of p such thats the ratio of ap to pd is 2:1

The point P on line AB such that the ratio of AP to PB is 2:1 is P = (0, 3)

Step-by-step explanation:

The dimension of the graph can be taken as 1 box = 1 unit

Therefore;

The coordinates of the point A = (-2, -7)

The coordinates of the point B = (1, 8)

For the a point P that gives the ratio AP to PB = 2:1 is given as follows;

The fraction of AP to AB = 2/(2 + 1)×AB = 2/3 × AB

Which gives;

The coordinate of the point P = (-2 + 2/3×(1 - (-2)), -7 + 2/3×(8 - (-7)))

P = (0, 3)

Therefore;

The coordinates of P such that the ratio of AP to PB is 2:1 is P = (0, 3).

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step-by-step explanation:

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