A friut stand sells watermelons during the summer. The revenue for selling x watermelons is given by f(x)=2.5x. The team's profit is $25 more than 60% of the revenue for selling x watermelons. Write a funcction g to model the profit. Then find the profit for selling 44 watermelons.

$91

Step-by-step explanation:

f(x) = 2.5 x

$25 more would + $25 to the function

60% = .6

Revenue is f(x) = 2.5x  which we have to multiply by the .6

g(x) = $25 + .6 (2.5 x)

If we have 44 watermelons then we plug in 44 for x

x = 44

g(x) = $25 + .6 (2.5*44)

g(x) = $25 + .6 (110)

g(x) = 25 + 66

g(x) = $91

The profit is $91

y=mx+b is the final answer!   : )