Which of the following circumstances would likely make factoring the best method for solving a quadratic equation? Question 3 options:

A quadratic that is prime

The leading coefficient is zero

The leading coefficient is not 1 and the constant is a large number

The difference of 2 perfect squares

Option D.

Step-by-step explanation:

We need to find the circumstances that would likely make factoring the best method for solving a quadratic equation.

A quadratic equation is prime if its factors can not possible. So, option A is incorrect.

In a quadratic equation leading coefficient can not be zero. So, option B is incorrect.

For large numbers (coefficient or constant), quadratic formula is best method. So, option C is incorrect.

The difference of 2 perfect squares is:

In this case factoring is the best method.

Therefore, the correct option is D.

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads