Explain why a quadratic equation with a positive discriminant has two real solutions, And why a quadratic equation with a negative discriminant has no real solution, And a quadratic equation with a discriminant of zero has one real solution.

The given equation is -2x^2 = -8x + 8

This can be rewritten as 2x^2 - 8x + 8 = 0

Here the value of a =2, b = -8 and c = 8

Discriminant = b^2 - 4ac

Now plug in the above values in the discriminant, we get

= (-8)^2 - 4*2*8

= 64 - 64

= 0

Here the discriminant is 0, so we will get one real root.

The discriminant is equal to 0, which means the equation has one real number solution.

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a. 19,958,400

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