There are five consecutive odd integers. The sum of the three smallest is 3 more than the sum of the two largest. Find the integers.

The answer is "".

Step-by-step explanation:

In word problem, it is solved by 2k+1, among the most common forms of even an, unlike number.

Let another odd integer become 2k+1.....(a)

(2K+1)+(2k+3)+(2k+5)=(2k+7)+(2k+9)+3(to take the left side 3 extra)  

Quality for the k:

put the value of k, in the equation (a):

There are also 11, 13, 15, 17, and 19 episodes.  

Let's test it! Let's test it. 11+13+15=39  

17+ 19 = 36.  

So we're right, the first 3 integer numbers are 3 more than the last 2.

binomial distribution

median= 2

range = 7-0 = 7

how to find median?

no. of term=28

median=(28+1)/2=14.5th term

the 14th and 15th term are 2, therefore the median is (2+2)/2 = 2

i used to know but i learned it a long time ago sorry

step-by-step explanation: