Calculus Ch. 1.2 Classwork Problems Evaluating limits Graphically

8) 1

9) -4

10)  -3

11)  -1

12)  1

13)  doesn't exist

14)  1

15)  doesn't exist

Step-by-step explanation:

8) when we approach x=-8 from left and from right, the function tends towards the value 1

9) when we approach x = -7, from the left the function gets towards 0, while when we approach it from the right it gets closer to -4

10) f(-3) = -3

11) When x approaches the value 4 from the left and from the right, f(x) gets closer to -1

12) f(4) is defined as 1

13) f(6) doesn't exist

14)  When x approaches 6 from the left and from the right, the function approaches 1

15)  When x approaches the value 7 from the left the function gets closer to 2, while when we approach x = 7 from the right the function gets toward 7. Because of this discrepancy, the limit doesn't exist.

yes

step-by-step explanation:

lol we need to see what the question is asking about

step-by-step explanation: