Check each equation whose graph is the line that contains the points (4, -7) and (1,5).
y=-4x + 9
y=-4x – 23
y-1 =-4(X-5)
y + 7 = -4(x – 4)
4x + y = 9
DONE

Points P ( 4 , - 7 ) and  Q ( 1 , 5 ) belong to the equations:

1  ;  4  ;  and  5

Step-by-step explanation:

Equations 1 ; 4 and 5 are the same equation

Equation 1    y  =  - 4*x + 9

Equation 4

y + 7 = - 4 * ( x - 4 )   ⇒  y + 7  = - 4*x + 16   ⇒ y = - 4*x - 7 + 16

y = -4*x + 9

Equation 5

4*x + y = 9    ⇒ y = - 4*x + 9

Now for the equation y = - 4*x + 9

P ( 4 , -7)

For x = 4    y = - 4*(4) + 9     ⇒  y = - 16 +  9    ⇒  y = - 7

Then point P is in the line  y = - 4*x + 9

Point Q (1 , 5 )

For x = 1    y = - 4 * ( 1) + 9     ⇒  y = - 4 + 9    ⇒  y = 5

Point Q is in the line y = - 4*x + 9

Equation 2

y = - 4*x - 23

Point P ( 4 , - 7 )

For x = 4       y  = 16 - 23   y  = - 7

Point P is in the line

Point Q

For x = 1     y = - 4 *(1) - 23      ⇒   y = - 27

Then poin Q is not in the line

Equation 3

y - 1 = - 4 * ( x - 4 )

y  - 1 =  -4*x + 16    ⇒   y  = - 4*x + 17

Point P ( 4 , - 7 )

For x = 4

y = - 16 + 17   ⇒ y = 1    

Point P is not in the line

And Point Q ( 1 , 5 )

For  x = 1

y = - 4* ( 1 ) + 17    ⇒  y  = 13    Q is not in the line

answear:

a

step-by-step explanation: a

the answer is c.

step-by-step explanation: