Which value of x makes this equation true? -8(x+5) = -3x - 7+ x-3
A.
1 =
-
NIP
B.
I = -5
C.
=
1
D.
= 12

x=-5

Step-by-step explanation:

opening the bracket on the LHS, we have

-8x-40= -3x+x-7-3

-8x-40= -2x-10

collecting like terms

-8x+2x= -10+40

-6x= 30

divide both sides by -6

x= -5

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.