The length of a rectangular field is 45 ft greater than its width, w ft. how much fencing is needed to enclose the field and divide it into two parts as shown?

Length of fencing needed = 4x + 45

Step-by-step explanation:

Assume;

Width of rectangle = x

So,

Length of rectangle = x + 45

Find:

Length of fencing needed

Computation:

Length of fencing needed = 2(l+b) + b

Length of fencing needed = 2(x+45+x) + x

Length of fencing needed = 2(2x+45) + x

Length of fencing needed = 4x + 45

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)