The perimeter of a rectangular garden is 108 meters. The length is 6 meters longer than twice the width, find the dimensions of the garden

width=16

length=38

Step-by-step explanation:

perimeter of a rectangle=2(length+width)

108/2=length+ width

54=length+ width

54-width=length

also:

length-6= 2×width

length=2width +6

now you can put the length we found, in the second equation:

54-width=2width+6

54-6=2width+width

48=3width

width=16

now do the exact same thing with one of the equations we created in the beginning.

either this:

54-width=length

or this:

length=2width +6

as the 1st one is simpler, I use that:

54-(16)=length

length=38

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)