Rectangle EFGH has verticles at E(7,7), F(1,5), G(2,2), and H(8,4). How many units is the perimeter of rectangle EFGH. Answer choices: A. 20 B. 10√13 C. 5√10 D. 6√10

Step-by-step explanation:

Given the vertices of a rectangle EFGH as E(7,7), F(1,5), G(2,2), and H(8,4), the perimeter if the rectangle will be the sum total of all the sides of the rectangle.

Using the expression Perimeter of rectangle EFGH = EF+FG+GH+EH

Taking the distance between adjacent vertices to get the length of each segment using the formula;

D = √(x₂-x₁)²+(y₂-y₁)²

For segment EF with vertices E(7,7), F(1,5);

EF = √(1-7)²+(5-7)²

EF = √(-6)²+(-2)²

EF = √36+4

EF = √40

EF = 2√10

For segment FG with vertices F(1,5) and G(2,2);

FG = √(2-1)²+(2-5)²

FG = √(1)²+(-3)²

FG = √1+9

FG = √10

For segment GH with vertices G(2,2), and H(8,4)

GH = √(8-2)²+(4-2)²

GH = √(6)²+(2)²

GH = √36+4

GH = √40

GH = 2√10

For segment EH with vertices E(7,7), and H(8,4)

EH = √(8-7)²+(4-7)²

EH = √(1)²+(-3)²

EH = √1+9

EH = √10

Since  perimeter of rectangle EFGH = EF+FG+GH+EH

Perimeter of rectangle EFGH = 2√10+√10+2√10+√10

Perimeter of rectangle EFGH = 6√10

the answer

b. they are parallel and will never intersect.