Please help me check my answers for these problems Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places)

Numbers given: -2.5,-2.9,-2.95,-2.99,-2.999,-2.999 9

-3.5,-3.1,-3.01,-3.001,-3.0001

Lim (x--> -3)

Determine the infinite limit

1)

Lim (x--> )

2)

Lim (x-->1)

me! what did you put for this question?

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

bobby has the most candy because 7/8= .875

step-by-step explanation: