I need help please! If m∠ABD=76°, what are m∠ABC and m∠DBC? If m∠JKH=77° then m∠NDF=__

m<ABC = 41°

m<DBC = 35°

m<NDF = 77°

Step-by-step explanation:

Problem 1:

Given, m<ABD = 76°, m<ABC = (7x - 1), m<DBC = (5x + 5)

m<ABC + DBC = m<ABD (angle addition postulate)

(substitution)

Solve for x

Collect like terms

Subtract 4 from each side

Divide each side by 12

Find m<ABC

m<ABC = (7x - 1)

Plug in the value of x

m<ABC = 7(6) - 1 = 42 - 1 = 41°

Find m<DBC

m<DBC = (5x + 5)

Plug in the value of x

m<DBC = 5(6) + 5 = 30 + 5 = 35°

Problem 2:

<JKH and <NDF are corresponding angles. Corresponding angles are congruent.

Given that m<JKH = 77°, m<NDF = 77° (corresponding angles are equal).

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people