An error has been made in subtracting the two polynomials as shown in the student work. (6x2 – 4x – 5 ) – (3x2 – 7x + 2) = How do you correctly subtract the two polynomials? Identify: Terms: Coefficient of "x2 ":Coefficient of "x":

3x^2 + 3x - 7

Step-by-step explanation:

Given:

(6x^2 – 4x – 5 ) – (3x^2 – 7x + 2)

The correct way of subtracting the polynomial is by changing the sign of each term of the second polynomial. Like this

= 6x^2 – 4x – 5 – 3x^2 + 7x - 2

Collect like terms

= 6x^2 - 3x^2 - 4x + 7x - 5 - 2

Simplify

= 3x^2 + 3x - 7

(6x^2 – 4x – 5 ) – (3x^2 – 7x + 2) = 3x^2 + 3x - 7

From the answer, the coefficient of x^2 is 3, coefficient of x is 3

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3