HURRY PLEASE if ray NP bisects angle MNQ and measure of angle MNQ= 8x + 12 and measure of PNQ= 78 degrees and measure of angle RNM= 3y -9, find the values of x and y

the measure of x is 18° and the measure of y is 29°

Step-by-step explanation:

Step 1

Find the measure of angle x

we know that

If ray NP bisects <MNQ

then

m<MNQ=m<PNM+m<PNQ > equation A

and

m<PNM=m<PNQ > equation B

we have that

m<MNQ=(8x+12)°

m<PNQ=78°

so

substitute in equation A

(8x+12)=78+78> 8x+12=156> 8x=156-12

8x=144> x=18°

Step 2

Find the measure of angle y

we have

m<PNM=(3y-9)°

m<PNM=78°

so

3y-9=78> 3y=87> y=29°

therefore

the answer is

the measure of x is 18° and the measure of y is 29°

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2