Determine how many terms should be used to estimate the sum of the entire series with an error of less than 0.001.

9

Step-by-step explanation:

Tₙ ₊ ₁  < 0.001

1 / ( (n+1) 3 +1 ) < 0.001

(n+1)3 + 1 > 1000

(n+1)3 > 999

n+1 > 9.9966

n = 8.9966 => n = 9

I should take n = 9 to be sure that the error is less than 0.001.

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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your answer is -9

step-by-step explanation: