-2, -1, -1, 0, -1, 1, -2, … Find the next 3 numbers in the sequence above. Describe the pattern.

 -2, -1, -1, 0, -1, 1, -2, -1, -1, 0

Step-by-step explanation:

When you are looking at the problem

" -2, -1, -1, 0, -1, 1, -2, … Find the next 3 numbers in the sequence above. Describe the pattern."

you want to observe the pattern, now For example

1, 2, -1, -4 .. and so on

so there is a pattern here if looked at hard enough it goes 1 - 2 = -1 - -3 = -4

when you find the pattern it gets really easy.

Hope this helped!

answer: do we write it

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.