In what order should you stack the machines so that when 6 is dropped into the first machine, and all four
machines have had their effect, the last machine's
output is 11 ?
f(x)=√x
g(x) -(x - 2)2
h(x) = 2X-7
k(x) = - - 1
Order the functions below so that you use all four
functions.
= k(
k(x) = -2 -1
h(x)=2x - 7

Step-by-step explanation:

Given

Input = 6

Expected Output = 11

Process:

Required

Arrange the processes to give an output of 11

To answer this question, I'll make use of trial by error methods.

After some attempts, the following is the order of the processes;

Set x = 6

Substitute 6 for x in g(x)

Substitute -16 for x in k(x)

Substitute 7 for x in h(x)

Substitute 121 for x in f(x)

Hence, the processes is:

1/5

step-by-step explanation:

the dice has 6 sides and there is only one 5 in a dice.

probability for j is 1/4

while

a is 1/6