I need helpp asap Suppose PQR is rotated 90 degrees about the origin, (0,0). Find the coordinates of P’ , Q’ , and R’. Then sketch P’Q’R’

The coordinates of P’ are __
The coordinates of Q’ are __
The coordinates of R’ are __

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

i think the amount would be $140.62