5. Diagram 1 shows an isosceles triangle with a base of 4y cm and a height of (y + 5) cm. Diagram 2 shows a square with sides of y cm.
The area of the triangle is more than the area of the square by 39 cm². Calculate the difference
in perimeter between both shapes.

Height of the triangle = y + 5 cm
Length of base = 4y cm
Height of the square = y cm

Can someone answer it, and plot it, for 20 points and brainliest answer? p.s. they're the same ! : )

Let the closed interval [a , b] be the domain of function f. the domain of f(x - 3) is given by (a) the open interval (a , b) (b) the closed interval [a , b] (c) the closed interval [a - 3 , b - 3] (d) the closed interval [a + 3 , b + 3]

Which is a true statement comparing the graphs of x^2/6^2-y^2/8^2 = 1 and x^2/8^2-y^2/6^2 the foci of both graphs are the same points. the lengths of both transverse axes are the same. the directrices of = 1 are horizontal while the directrices of = 1 are vertical. the vertices of = 1 are on the y-axis while the vertices of = 1 are on the x-axis.