A triangle with vertices at A(0,0), B(0,4), and C(6,0) is dilated to yield a triangle with vertices at A(0,0), B(0,10) and C(15,0). The origin is the center of dilation. What is the scale factor of the dilation? A. 1.5
B. 2
C. 2.5
D. 3

The scale of dilation is 2.5

Step-by-step explanation:

K · ( 0, 0 ) = ( 0 , 0 )

k · ( 0 , 4 ) = ( 0 , 10 )

k · ( 6, 0 ) = ( 15, 0 )

k = 15/6 = 10/4 = 2.5

The scale of dilation is 2.5

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)