A waterwheel has a radius of 5 feet. the center of the wheel is 2 feet above the waterline. you notice a white mark at the top of the wheel. how many radians would the wheel have to rotate for the white mark to be 3 feet below the waterline? a) 2pi radians
b) 3pi/2 radians
c) pi radians
d) pi/2 radians

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft

answer: it is a.,b.,d.

step-by-step explanation: