A sequence of numbers consists of natural numbers that are not perfect squares. What is the 1000th member of this
sequence?

Given :

A sequence of numbers consists of natural numbers that are

not perfect squares.

To Find :

The 1000th member of this  sequence .

Solution :

Now , and .

So , there are 31 numbers before 1000 which are perfect square .

Therefore , the is 1000+31 = 1031 .

Also , the first perfect square after 1000 is 32 .

So , we have to continue to 1031 + 1 = 1032 to compensate for the 32nd square.

Therefore , the 1000th member of this  sequence is 1032 .

Hence , this is the required solution .

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