The first aircraft has 89 more seats than the second aircraft. The third aircraft has 31 fewer seats than the second aircraft. If their total number of seats is 418, find the number of seats for each aircraft.

I think number 1=209

number 2=120

number 3=89

Step-by-step explanation:

x= 1st aircraft

y=2nd aircraft

z=3rd aircraft

x=y+89

y=z+31

z=y-31

x+y+z=418

y+89+z+31+y-31=418

2y+89+z=418

2y+z=329

2y+(add z)

2y+y-31=329

3y=360

y=120

x=120+89=209

z=120-31=89

mxb67

step-by-step explanation: