Hal used the following procedure to find an estimate for V82.5. Step 1: Since g2 = 81 and 102 - 100 and 81 < 82.5< 100, V82.5 is between 9 and 10.
Step 2: Since 82.5 is closer to 81, square the tenths closer to 9.
9.02 - 81.00
9.12 - 82.81
9.22 = 84.64
Step 3: Since 81.00 < 82.5 < 82.81, square the hundredths closer to 9.1.
9.082 - 82.44
9.092 = 82.62
Step 4: Since 82.5 is closer to 82.62 than it is to 82.44, 9.09 is the best approximation for 82.5.
in which step, if any, did Hal make an error?

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

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