Use the difference quotient to calculate the average rate of change across the following intervals. Difference quotient of d(t): 3t^2 + 5th – 2 The interval 2 to 3:

The interval 2 to 2.5:

The interval 2 to 2.1:

Ok, we have:

d(t) = 3*t^2 + 5*t - 2.

The first interval is:

(2, 3)

and remember that, for an interval (a,b), the difference quotient is:

D = (f(b) - f(a))/(b -a)

Then in this first interval we have:

So the average rate of change in (2,3) is 20.

now, in (2, 2.5) we have:

So here the rate of change is 9.25

And in the interval (2, 2.1) we have:

So in this interval the rate of change is 1.73

d? maybe

step-by-step explanation: