What are the x-intercepts of the graph of the function f(x) = x^2 + 4x – 12? (-6,0). (2.0)
(2. -16). (0, -12)
(-6.0), (2, -16), (2, 0)
(0.-12).(-6, 0), (2, 0)

(- 6, 0 ) , (2, 0 )

Step-by-step explanation:

To find the x- intercepts let f(x) = 0, that is

x² + 4x - 12 = 0 ← in standard form

(x + 6)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 6 = 0 ⇒ x = - 6

x - 2 = 0 ⇒ x = 2

Thus the x- intercepts are (- 6, 0 ), (2, 0 )

the answer is simply just 6n add the two together as they have an n

the answer is 1/4

step-by-step explanation: