A small town's raffle has 85 entries and 3 gift baskets that three different people could win. What is the probability of winning a gift basket if you have 1 of the entries

Step-by-step explanation:

This problem is on probabilty since there are a number of entries to be selected from which are 85 entries, the chances of winning one of the prices if selected is

the number of entries you have/ total number of entries

given that the total entry is 85

and that you have one entry

Since there are three gift baskets you have three chances to win one.

hence there will be a total of three draws, and after each draw, there won't be a replacement of the previous winner (as the winners are three distinct persons).

Hence the probability of winning a draw for the gift basket is  

=1st draw+2nd draw+3rd draw

= 1/85+1/84+1/83

= 0.0117+0.0119+0.012

= 0.035

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

ratio is 2 : 9

the answer is three

13.5 : 3