What is the slope of the line from 0-10 seconds? position (m)
80
60
40
20
-20
-401
10
20
30
40
50
time (sec)
6 m/s
.17 m/s
b
С
- 17 m/s
d
-6 m/s

B

Step-by-step explanation:

The answer can't be C/D because the graph goes up between 0 - 10 sec, thus the value of the slope should be positive, not negative

As you can see in the pic, the value of the slope is 1/6 and if you convert it, the result is 0.1666666667 ~ 0.17

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the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12