Write the equation of the line that perpendicular to 4x+5y=20 an that passes through the point (-4,1)

y = (5/4)x + 6

Step-by-step explanation:

The 1st line's equation is:

● 4x + 5y = 20

Substract 4x from both sides

● 4x + 5y - 4x = 20 - 4x

● 5y = 20 -4x

● 5y = -4x + 20

Divide both sides by 5

● 5y/5 = (-4x + 20)/5

● y = (-4/5)x + 4

● y = -0.8x + 4

Let m be the slope of the second line

The lines are perpendicular so the product of their slopes equals -1

Then: m × (-0.8) = -1

● m × (-0.8)= -1

● m = -1/(-0.8)

● m = 1.25

y = 1.25x + b

b is the y-intercept of the line.

To get it replace by the coordinates of a point.

We are given that the line passes through (-4,1)

● y = 1.25x + b

● 1 = 1.25 × (-4) + b

1.25 is 5/5

● 1 = (5/4) × (-4) + b

● 1 = -5 + b

Add 5 to both sides

● 1 + 5 = -5 + b + 5

● b = 6

So the equation is

● y = (5/4)x + 6

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

c(x)= 6x + 3

step-by-step explanation: