Q is the midpoint of PR. If PQ = 8x+11 and QR = 14x-1, what is the value of x?

x=2

Step-by-step explanation:

PQ =QR  if Q is the midpoint

8x+11 = 14x-1

Subtract 8x from each side

8x+11 -8x = 14x-1-8x

11 = 6x-1

Add 1 to each side

11+1 = 6x-1+1

12 = 6x

Divide each side by 6

12/6 = 6x/6

2 =x

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

you already gave the answer

step-by-step explanation: