What is the inverse of the relation{(-2,-4), (-4, 3), (7,9),(-3,-3)}?

Step-by-step explanation:

Question (3).

Given set of coordinates of the function is {(-2, -4), (-4, 3), (7, 9), (-3, -3)}

If a function has a point (x, y), inverse function will be,

f(x, y) → f(y, x)

In other words, a point lying on function 'f' when reflected across a line y = x,

(x, y) → (y, x)

Therefore, inverse of the relation given will be defined by the set of points,

{(-4, -2), (3, -4), (9, 7), (-3, -3)}

Option (3) will be the answer.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0