the length of a rectangle is three times it’s width. if the area of the rectangle is 300 yd^2, find its perimeter.

80 yards

Step-by-step explanation:

Using the area formula, A = lw, set up an equation where w represents the width.

The length can be represented by 3w because it is 3 times the width:

A = lw

300 = (3w)(w)

300 = 3w²

Solve for w:

300 = 3w²

100 = w²

10 = w

So, the width is 10 yards.

The length will be 30 yards since the length is 3 times the width.

Then, add the lengths and widths together to find the perimeter:

10 + 10 + 30 + 30

= 80

So, the perimeter is 80 yards

i don't even know man. edge inuity be messing with us. i had to ask a question too.

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)