There are three consecutive integers such as twice the sum of the smallest and largest is eight more than twice the largest. Find the smallest integer in the sequence someone pleas answer!!!

Let the consicutive numbers are

x , x+1 , x+2

Step-by-step explanation:

Sum of the smallest and largest number is 8 more than the twice of largest number.

x + x +2 = 8 + 2( x + 2 )

2x + 2 = 8 + 2x + 4

2x - 2x = 12 - 2

0 = 10

It is not possible according my calculation.

c

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)