How to calculate y=6x^2+1

Hi there!

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⇒ Graph :

∴ Rewrite the equation in vertex form.

⇒

∴ Use the vertex form, , to determine the values of and

∴ Since the value of is positive, the parabola opens up.

⇵

∴ Find the vertex .

∴ Find , the distance from the vertex to the focus.

∴ Find the focus.

∴ Find the axis of symmetry by finding the line that passes through the vertex and the focus.

∴ Find the directrix.

∴ Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

⇒ Vertex:

⇒ Focus:

⇒ Axis of Symmetry:

⇒ Directrix:

∴ Select a few values, and plug them into the equation to find the corresponding  values. The values should be selected around the vertex.

Hope this helped you!

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

5días gucgivuzu 32 horas y horas 6y t7